1/2(x-2)^2-5=0

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Solution for 1/2(x-2)^2-5=0 equation: 


x in (-oo:+oo)

(1/2)*(x-2)^2-5 = 0

1/2*(x-2)^2-5 = 0

1/2*(x-2)^2-5 = 0

1/2*x^2-2*x-3 = 0

1/2*x^2-2*x-3 = 0

1/2*x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1/2*4)

DELTA = 10

DELTA > 0

x = (10^(1/2)+2)/(1/2*2) or x = (2-10^(1/2))/(1/2*2)

x = 10^(1/2)+2 or x = 2-10^(1/2)

(x+10^(1/2)-2)*(x-10^(1/2)-2) = 0

(x+10^(1/2)-2)*(x-10^(1/2)-2) = 0

( x+10^(1/2)-2 )

x+10^(1/2)-2 = 0 // - 10^(1/2)-2

x = -(10^(1/2)-2)

x = 2-10^(1/2)

( x-10^(1/2)-2 )

x-10^(1/2)-2 = 0 // + 10^(1/2)+2

x = 10^(1/2)+2

x in { 2-10^(1/2), 10^(1/2)+2 }

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